Answer:

The length of either of the remaining equal sides are 7/5 cm each.

Step-by-step explanation:

Base of isosceles triangle = 4/3 cm

Perimeter of triangle = 62/15

Let the length of equal sides of triangle be ‘S’.

2S = (62/15 – 4/3)

2S = (62 – 20)/15

2S = 42/15

S = (42/30) × (1/2)

S = 42/30

S = 7/5

So, length of either of the remaining equal sides are 7/5 cm each.

Verified answer

Step-by-step explanation:

•Given • :-

• The base of an Isosceles triangle is 4/3 cm
• The perimeter of the triangle is 4 2/15 cm

• To find • :-

• The length of equal sides .

• Solution • :-

Given that

Let the length of the equal sides of an Isosceles be " a cm " each

Length of the base of the Isosceles triangle

= 4/3 cm

We know that

The perimeter of an Isosceles triangle = 2a+b units

The perimeter of the Isosceles triangle

= 4 2/15 cm

= [(4×15)+2]/15 cm

= (60+2)/15 cm

= 62/15 cm

Therefore, 2a+b = 62/15

=> 2a + (4/3) = 62/15

=> 2a = (62/15)-(4/3)

LCM of 15 and 3 = 15

=> 2a = (62-20)/15

=> 2a = 42/15

=> a = (42/15)/2

=> a = 42/(15×2)

=> a = 21/15 cm

=> a = 7/5 cm

=> a = 1 2/5 cm

Therefore, required length = 1 2/5 cm

• Answer• :-

The length of the equal sides is 7/5 cm or

1 2/5 cm each

• Used Formula • :-

• The perimeter of an Isosceles triangle = 2a+b units
• a = length of equal sides
• b = base of the triangle