Answer:

answer is =9/12

see the attachment

Step-by-step explanation:

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Let the numerator and denominator of a rational number be 3x and 4x respectively.

[x is an assumed common multiple].

As per the question ::

[tex] \sf \dfrac{3x}{4x + 3} = \dfrac{3}{5} [/tex]

[tex] \sf \: 15x = 3(4x + 3)[/tex]

[tex] \sf \: 15x = 12x + 9[/tex]

[tex] \sf \: 15x \: - 12x = 9[/tex]

[tex] \sf \: 3x = 9[/tex]

[tex] \boxed{ \sf \: x = 3 } \dots\bigstar[/tex]

Therefore, the numerator (3x) = 3×3 = 9

Denominator (4x) = 4×3 = 12

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Required Rational number would be 9/12