Step-by-step explanation:

Capacity = Volume of a rectangular tank = Area of base * height

Area of base = 2.6*10^4 cm^2

1 cm = 1/100 m

Area of base = 2.6*10^4 * (1/100) * (1/100) m^2

= 2.6 m^2

Volume =Area of base * height

5.2 = 2.6 *h

h = 5.2/2.6

h=2m

Verified answer

Step-by-step explanation:

[tex] \large \underbrace \mathfrak {Solution :-}[/tex]

We know that:

[tex] \boxed{ \sf \: Volume \: of \: cuboid = l \times b \times h}[/tex]

[tex] \large{ \sf \: where} \begin{cases} \small\sf \: I = length \: of \: rectangular \: tank \\ \sf \small \: b \: = breadth \: of \: the \: rectangular \: tank \\ \sf \small \: h = height \: of \: the \: rectangular \: tank \end{cases}[/tex]

And -

[tex] \sf \large{ \: 1m^ 2 =10^ 4 cm^ 2}[/tex]

Also -

[tex] \large \sf \: the \: area \: of \: rectangle = I × b[/tex]

According to given :

[tex] \sf \: Volume = I \times b \times h = 5.2m ^ 3 \\ \sf Area \: of \: its \: base=l \times b=2.6 \times 10^ 4 cm^ 2 \\ \sf = I \times b=2.6 m^ 2 \\ \\ \sf Volume \: of \: cuboid \\ \sf \: = area \: of \: base \times h=5.2 m^ 3 \\ \sf = h= \frac{5.2}{2.6} \\ \sf =2 m[/tex]

Hence, height of rectangular tank = 2m