GIVEN :

7th term of the AP = 20

i.e : a + 6d = 20 ─────> eq (1)

13th term of the AP = 32

i.e : a + 12d = 32 ─────> eq (2)

subtracting eq (1) from eq (2)

a + 12d - 32 = a + 6d - 12

=> 6d = 12

=> d = 12/6

=> d = 2

Now we need to find a

so putting the value of d in eq (2)

a + 6d = 20

=> a + 6(2) = 20

=> a + 12 = 20

=> a = 20 - 12

=> a = 8

AP SEQUENCE : a, a + d, a + 2d, a + 3d

a = 8

d = 2

8 , 8 +2 , 8 + 2(2) , 8 + 3(2)

AP : 8 , 10 , 12 , 14

HOPE THIS WILL HELP YOU... ❤