Answer:

[tex] \sqrt{1 + 3 + 5 + ... + 4043} [/tex]

1 + 3 + 5 + ... + 4043

sum of n odd natural numbers = n²

to find n,

a = 1, d = 3 - 1 = 2, l = 4043

[tex]n = \frac{l - a}{d} + 1[/tex]

[tex] = \frac{4043 - 1}{2} + 1[/tex]

[tex] = \frac{4042}{2} + 1[/tex]

n = 2021 + 1

= 2022

1 + 3 + 5 + ... + 4043 = 2022²

[tex] \sqrt{1 + 3 + 5 + ... + 4043} = \sqrt{ {2022}^{2} } [/tex]

[tex] \sqrt{1 + 3 + 5 + ... + 4043} = 2022[/tex]