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❗❗✴✴✴✴SHORT METHOD TO FIND HYBERDISATION✴✴✴✴
Any easy method✔✔❗❗✌✌
❗❗✴✴✴✴SHORT METHOD TO FIND HYBERDISATION✴✴✴✴
Any easy method✔✔❗❗✌✌
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–BEGIN SHORTCUT–
Here’s what you do:
Look at the atom.
Count the number of atoms connected to it (not bonds – atoms).
Count the number of lone pairs attached to it.
Add these two numbers together.
If it’s 4, your atom is sp3.
If it’s 3, your atom is sp2.
If it’s 2, your atom is sp.
(If it’s 1, it’s probably hydrogen!)
This works in at least 95% of the cases you will see in Org 1.
Here’s some simple examples.
sp3 hybridization: sum of attached atoms + lone pairs = 4
sp2 hybridization: sum of attached atoms + lone pairs = 3
sp hybridization: sum of attached atoms + lone pairs = 2
Where it can start to get slightly tricky is in dealing with line diagrams containing implicit (“hidden”) hydrogens and lone pairs. Chemists like time-saving shortcuts just as much as anybody else, and learning to quickly interpret line diagrams is as fundamental to organic chemistry as learning the alphabet is to written English.
Remember:
Just because lone pairs aren’t drawn in on oxygen, nitrogen, and fluorine doesn’t mean they’re not there.
Assume a full octet for C, N, O, and F with the following one exception: a positive charge on carbon indicates that there are only six electrons around it. [Nitrogen and oxygen bearing a formal charge of +1 still have full octets].
hope it's helps you