Step-by-step explanation:

3+2x

x+2x

3x

x

=1−x

=1−3

=−2

=

3

−2

Now, to check the result. We have to substitute

3

−2

in the place of x in given equation.

So, we get LHS of given equation as,

LHS

=3+2×(

3

−2

)

=3−2×

3

2

=3−

3

4

=

3

5

Now, RHS will be,

RHS

=1−(

3

−2

)

=1+

3

2

=

3

1×3+2

=

3

5

∴LHS=RHS

Hence, the result is verified

Step-by-step explanation:

Solutions :

1)

Given that (2x - 3) / 3 = 1 - (2/3)

=> (2x-3)/3 = (3-2)/3 => (2x-3)/3 = 1/3

On cancelling 3 both sides then

=> 2x-3=1

=> 2x = 1+3

=> 2x = 4

= x = 4/2

=> x = 2

Therefore, The value of x = 2

2)

Given that (y / 9) - (y / 12) = 1/103

LCM of 9 and 12 = 36

=> [(4xy)-(3×y)]/36 = 1/103

=> (4y - 3y) / 36 = 1/103 => v / 36 = 1/103

=> v = 36/103

Therefore, The value of y = 36/1033)

Given that 2y + 3 = 5y + 7

2) If y = = 36/103 then LHS becomes

(y/9)-(y/12)

= [(36/103)/9]-[(36/103)/12)]

[36-(103×9)]-[36-(103×12)]

= [(36×4)-(36×3)]/(36×103)

[36(4-3)]/(36×103)

= 36/(36×103)

=1/103)

= RHS

LHS RHS is true for y = 36/103

3)If y = -4/3 then LHS becomes 2y+3

2(-4/3)+3

= (-8/3)+3

= (-8+9)/3

= 1/3

and RHS becomes 5y+7

= 5(-4/3)+7

= (-20/3)+7

=(-20+21)/3

= 1/3

ΔLHS RHS is true for y=-4/3

Verified the given relations in the given problems.

=>2y-5y = 7-3

=>-3y = 4

=> y = 4/- 3

=> y = - 4/3

Therefore, y = 4/3

Answers :

1) x = 2

2) y = 36/103

3) y = - 4/3

Check :

1)If x = 2 then LHS becomes

[2(2) - 3] / 3

= (4-3)/3

= 1/3

and RHS = 1-(2/3) = (3-2)/3 = 1/3

LHS RHS is true for x = 2

21lf v = 36/103 then IHS hecomes