Answer:
p−1,p+3,3p−1 are in A.P.
∴2(p+3)=p−1+3p−1
⇒2p+6=4p−2
⇒2p=8
∴p=4
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Answers & Comments
Answer:
p−1,p+3,3p−1 are in A.P.
∴2(p+3)=p−1+3p−1
⇒2p+6=4p−2
⇒2p=8
∴p=4