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Answer:

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[tex]y=1+x1−xy=(1+x)(1−x)(1−x)(1−x)y=1−x21−x−(1)⇒dxdy=(1−x2)21−x2dxd(1−x)−(1−x)dxd(1−x2)⇒dxdy=1−x2−1−x2+(1−x).1−x2x⇒(1−x2)dxdy=1−x2−1+x2+x−x2⇒(1−x2)dxdy=1−x2−1+x⇒(1−x2)dxdy=−(1−x21−x)

From (1)

(1−x2)dxdy=−y(1−x2)dxdy+y=0

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