[tex] \boxed{ \huge\purple{Q \sf{uestion}}}[/tex][tex] \boxed{ \sf{find \: the \: area \: of \: a \: rectangle\: whose }} \\ \boxed{ \sf{\: length \: is \: \pink{2.5cm} \: and }\: }\\ \boxed{\sf{breadth \: is \: \pink{1.3cm.}}} \\ [/tex]please also write Step-by-step. Created by mksinghmrityunjaysin.

tex]please also write Step-by-step

[tex]{\huge{\pmb{\underline{\underline{\boxed{\sf{\color{yellow}{♡}\:{\color{magenta}{Solution}{\color{yellow}\:{♡}}}}}}}}}} [/tex]

[tex]{ \huge{\sf{\underline{\underline{Given }}}}} :— [/tex]

[tex]\sf{Length = 2.5cm}[/tex]

[tex]\sf{Breadth = 1.3cm}[/tex]

[tex]{\sf{\underline {\underline{Applying \: \: formula }} \: {: \:-}}}[/tex]

[tex]\sf{→ \: } \: {\boxed{\sf{ \: Area= Length×Breadth}}}[/tex]

[tex]\sf{:⟹ \: } \: {\sf{Area= 2.5×1.3 \: cm²}}[/tex]

[tex]\sf{:⟹ \: } \: {\boxed{\sf{Area= 3.25 \: cm²}}}[/tex]

[tex]{\sf{Hence, \: \: area \: \: of \: \: the \: \: rectangle = 3.25 \: cm²}}[/tex]

[tex]{\color{purple}{\underline{\rule{100pt}{2pt}}}}{\color{orange}{\underline{\rule{100pt}{2pt}}}} [/tex]

[tex] \\ \diamond{\underline {\underline {\sf {\color{darkblue}{\;\; Area \; of \; Rectangle \; :-}}}}} \\ [/tex]

[tex] \\ \qquad{\underline {\boxed {\bf{ Area_{ \red{ \{rectangle \}}}\:= \: length\: \times breadth} \:}} }\red\bigstar \\ [/tex]

[tex] \\ {\sf{\color{green}{\underline{☆\: Putting \: Values \::-}}}} \\ [/tex]

[tex] \\ \sf \implies \: Area_{ \red{ \{rectangle \}}}\:= \: length\: \times breadth \\ [/tex]

[tex] \\ \sf \implies \: Area_{ \red{ \{rectangle \}}}\:= \: 2.5\: \times 1.3 \\ [/tex]

[tex] \\ \sf \implies \: Area_{ \red{ \{rectangle \}}}\:= \: 3.25 \\ [/tex]

[tex] \\ \implies{\underline{\boxed {\frak { Area_{ \red{ \{rectangle \}}}\:= \: 3.25 \: {cm}^{2} }}}} \; \purple\bigstar \\ [/tex]

[tex]\\ [/tex]

Therefore Area of Rectangle is 3.25 cm²

[tex] \\ \qquad\rule{150pt}{2pt} \\ [/tex]