solve for the x
1
[tex] \frac{x}{x - 2} = \frac{x \ + 3}{x + 2} - \frac{x}{ {x}^{2} - 4} [/tex]
2
[tex] \frac{x}{x + 1} + \frac{3x + 5}{ {x}^{2} + 4x + 3 } + \frac{2}{x + 3} [/tex]
pasecond na tanong ko na po ito pahelp po need now
1
[tex] \frac{x}{x - 2} = \frac{x \ + 3}{x + 2} - \frac{x}{ {x}^{2} - 4} [/tex]
2
[tex] \frac{x}{x + 1} + \frac{3x + 5}{ {x}^{2} + 4x + 3 } + \frac{2}{x + 3} [/tex]
pasecond na tanong ko na po ito pahelp po need now
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Answers & Comments
1. x = -3
2. x = 1
Step-by-step explanation:
hope it helps.
x / x-2 - x+3 / x+2 + x / (x-2)(x+2)=0
x(x+2)-(x-2)(x+3)+x / (x-2)(x+2)=0
x²+2x-(x²+3x-2x-6x)+x / (x-2)(x+2)=0
x²+2x-x²+x-6x+x / (x-2)(x+2)=0
2x + 6 / (x-2)(x+2)=0
2x + 6 = 0
2x = 6
x = - 3 [final answer]
x / x-2 - x+3 / x+2 + x / (x-2)(x+2)=0
x(x+2)-(x-2)(x+3)+x / (x-2)(x+2)=0
x²+2x-(x²+3x-2x-6x)+x / (x-2)(x+2)=0
x²+2x-x²+x-6x+x / (x-2)(x+2)=0
2x + 6 / (x-2)(x+2)=0
2x + 6 = 0
2x = 6
x = - 3 [final answer]