tex]Pasagot math Please po kase pinag sasabay ko arts ko at math T-T ...

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August 2022 1 2 Report

[tex]\huge{ \frac{2 {x}^{3} - 3x + 1}{ {x}^{2} + 4} }[/tex]
Pasagot math

Please po kase pinag sasabay ko arts ko at math T-T

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JasmineYUKI

Question:

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${\tt{\huge{ \frac{2 {x}^{3} - 3x + 1}{ {x}^{2} + 4} }}}$

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${\tt{2x}} \\ {\tt{ {x}^{2} + 4}} \: \: {\overline{\tt{ |2 {x}^{3} + 0 {x}^{2} - 3x + 1| }}} \\ {\tt{\underline{ \: \: - \: \: \: \: 2 {x}^{3} + 0 {x}^{2} - 8x}}} \\ {\tt{ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: - 11x + 1}}$

${\tt{ - 11x + 1}} \\ {\tt{2x + }} \: {\underline{ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: }} \\ {\boxed{\tt{ {x}^{2} + 4}}}$

Therefore the slant asymptote is y = 2x

$\huge{\boxed{\tt{y = 2x}}}$

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texstepsabc

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