square the following binomials. (show your solution use either a short or long method). 1-5
[tex](x + 5) {}^{2} [/tex]
[tex](3x - 1) {}^{2} [/tex]
[tex](2x - 4) { }^{2} [/tex]
[tex](3x + 2y) {}^{2} [/tex]
[tex](5 + 3b) {}^{2} [/tex]
note: (pls answer properly and show your solutions either short or long method) :)
[tex](x + 5) {}^{2} [/tex]
[tex](3x - 1) {}^{2} [/tex]
[tex](2x - 4) { }^{2} [/tex]
[tex](3x + 2y) {}^{2} [/tex]
[tex](5 + 3b) {}^{2} [/tex]
note: (pls answer properly and show your solutions either short or long method) :)
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Answer:
x² + 10x + 25
9x² - 6x + 1
4x² - 16x - 16
9x² + 12xy + 4y²
25 + 30b + 9b²
Step-by-step explanation:
(x + 5)²
= (x + 5) (x + 5)
= (x)(x) + (x)(5) + (x)(5) + (5)(5)
= x² + 5x + 5x + 25
= x² + 10x + 25
(3x - 1)²
= (3x - 1) (3x - 1)
= (3x)(3x) + (-3x)(1) + (-3x)(1) + (-1) (-1)
= 9x² -3x - 3x + 1
= 9x² - 6x + 1
(2x - 4)²
= (2x - 4) (2x - 4)
= (2x)(2x) + (2x)(-4) + (2x)(-4) + (-4)(-4)
= 4x² + -16x + 16
(3x + 2y)²
= (3x + 2y) (3x + 2y)
= (3x)(3x) + (3x)(2y) + (3x)(2y) + (2y)(2y)
= 9x² + 6xy + 6xy + 4y²
= 9x² + 12xy + 4y²
(5 + 3b)²
= (5 + 3b) (5 + 3b)
= (5)(5) + (5)(3b) + (5)(3b) + (3b)(3b)
= 25 + 15b + 15b + 9b²
= 25 + 30b + 9b²