اسلام علیکم !!

GIVEN:

In first sentence

M (men) = 20

W ( work/machine) = 5

D ( days) = 2

In second sentence

M' (men) = 8

D' ( days) = 2

TO FIND:

W'(work done) = ?

SOLUTION:

[tex] \frac{M \times D}{W} = \frac{M' \times D'}{W'} \\ [/tex]

on putting the values on above formula,we get:

[tex] ⟹\frac{20 \times 2}{5} = \frac{8 \times 3}{x} \\ [/tex]

[tex]⟹ \frac{40}{5} = \frac{24}{x} \\ [/tex]

on cross multiplication,we get:

[tex]⟹40 \times x = 24 \times 5 \\⟹x = \frac{24 \times 5}{40} \\ ⟹x = 3machines[/tex]

HENCE, 3 machines (W') are repaired by 8 men in 3 days.

Verified answer

Answer:

To solve this problem, we can use the concept of man-days, which represents the amount of work done by one person in one day.

Given that 20 men can repair 5 machines in two days, we can calculate the total man-days required to repair those machines as follows:

20 men * 2 days = 40 man-days

Therefore, it takes 40 man-days to repair 5 machines.

Now, we can calculate the number of machines repaired by 8 men in three days.

Let's assume X represents the number of machines repaired.

8 men * 3 days = 24 man-days

Since the total man-days required to repair 5 machines is 40,

we can set up a proportion to find the number of machines repaired by 8 men in three days:

40 man-days / 5 machines = 24 man-days / X machines

Cross-multiplying, we get:

40X = 5 * 24

40X = 120

Dividing both sides by 40:

X = 120 / 40

X = 3

Therefore, 8 men can repair 3 machines in three days.

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