A straight wire of mass 200g and length 1.5m carries a current of 2A. It is suspended in mid air by a uniform horizontal magnetic field B.A straight wire of mass 200g and length 1.5m carries a current of 2A. It is suspended in mid air by a uniform horizontal magnetic field B.
not that much but a [tex]l\!\!\!\!il\!\!\!\!tl\!\!\!\!tl\!\!\!\!ll\!\!\!\!e[/tex]
Lol that strange word is 'little"
not that much but a [tex]l\!\!\!\!il\!\!\!\!tl\!\!\!\!tl\!\!\!\!ll\!\!\!\!e[/tex]
Lol that strange word is 'little"
Answers & Comments
Answer:
0.65T
Explanation:
Given, mass of the wire = 200g = 0.2kg
Length of the wire = 15m
Current i = 2A
Magnetic field B =?
The force acting on the current carrying wire in uniform magnetic field
F = Bil sin θ
F = Bil ( ∵ θ = 90 o )
Weight of the wire w = mg = 0.2 × 9.8N
In the position of suspension
Bil = mg
B =
[tex] \frac{mg}{il} [/tex]
=
[tex] \frac{0.2 \times 9.8}{2 \times 15} [/tex]
= 0.65T
Answer:
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