[tex]{\huge{\colorbox {lavender}{✯Question✯࿐}}}[/tex] John is riding the Giant Drop at Canada. If John free falls for 2.6 seconds, what will be his final velocity and how far will he fall?
To calculate John's final velocity and the distance he falls during a free fall of 2.6 seconds, we can use the equations of motion for free fall. In the absence of air resistance, the equations of motion for free fall can be simplified.
1. Final Velocity (v):
The final velocity of an object in free fall can be calculated using the equation:
v = gt
Where:
v = final velocity (m/s)
g = acceleration due to gravity (approximately 9.81 m/s² on Earth)
t = time of free fall (in seconds)
Plugging in the values:
v = (9.81 m/s²) * (2.6 s) ≈ 25.506 m/s (rounded to three decimal places)
2. Distance Fallen (d):
The distance fallen during free fall can be calculated using the equation:
d = (1/2) * g * t²
Where:
d = distance fallen (m)
g = acceleration due to gravity (approximately 9.81 m/s² on Earth)
t = time of free fall (in seconds)
Plugging in the values:
d = (1/2) * (9.81 m/s²) * (2.6 s)² ≈ 33.993 meters (rounded to three decimal places)
So, John's final velocity after free falling for 2.6 seconds will be approximately 25.506 m/s, and he will fall approximately 33.993 meters.
To calculate John's final velocity and the distance he falls during a free fall, we can use the equations of motion for free fall under gravity. Assuming he starts from rest and neglecting air resistance:
1. Calculate the final velocity (Vf):
Vf = gt
Where:
- g is the acceleration due to gravity (approximately 9.8 m/s²)
Vf = (9.8 m/s²) * (2.6 s) = 25.48 m/s
So, John's final velocity will be approximately 25.48 meters per second.
2. Calculate the distance (d) he falls:
d = (1/2) * g * t²
d = (0.5) * (9.8 m/s²) * (2.6 s)² = 33.95 meters
John will fall approximately 33.95 meters during his free fall on the Giant Drop at Canada.[tex][/tex]
Answers & Comments
Explanation:
To calculate John's final velocity and the distance he falls during a free fall of 2.6 seconds, we can use the equations of motion for free fall. In the absence of air resistance, the equations of motion for free fall can be simplified.
1. Final Velocity (v):
The final velocity of an object in free fall can be calculated using the equation:
v = gt
Where:
v = final velocity (m/s)
g = acceleration due to gravity (approximately 9.81 m/s² on Earth)
t = time of free fall (in seconds)
Plugging in the values:
v = (9.81 m/s²) * (2.6 s) ≈ 25.506 m/s (rounded to three decimal places)
2. Distance Fallen (d):
The distance fallen during free fall can be calculated using the equation:
d = (1/2) * g * t²
Where:
d = distance fallen (m)
g = acceleration due to gravity (approximately 9.81 m/s² on Earth)
t = time of free fall (in seconds)
Plugging in the values:
d = (1/2) * (9.81 m/s²) * (2.6 s)² ≈ 33.993 meters (rounded to three decimal places)
So, John's final velocity after free falling for 2.6 seconds will be approximately 25.506 m/s, and he will fall approximately 33.993 meters.
Verified answer
Answer:
To calculate John's final velocity and the distance he falls during a free fall, we can use the equations of motion for free fall under gravity. Assuming he starts from rest and neglecting air resistance:
1. Calculate the final velocity (Vf):
Vf = gt
Where:
- g is the acceleration due to gravity (approximately 9.8 m/s²)
Vf = (9.8 m/s²) * (2.6 s) = 25.48 m/s
So, John's final velocity will be approximately 25.48 meters per second.
2. Calculate the distance (d) he falls:
d = (1/2) * g * t²
d = (0.5) * (9.8 m/s²) * (2.6 s)² = 33.95 meters
John will fall approximately 33.95 meters during his free fall on the Giant Drop at Canada.[tex][/tex]