1.)
Solution:
➪2(length+width)
➪2(10+6)
First, we solve the equation inside the parentheses which is 10 plus 6
10 + 6 = 16
Since "2" is just next to the parenthese we just simply multiply 2 with 16
16 x 2 = 32 meters
2.)
Since a square has 4 equal sides, the length of wire needed is 4 times the length of one side.
➪P = 4(120)
➪P = 480 m
3.)
First , we will solve for the perimeter of the regular hexagon:
➪P = 6(side)
➪P = 6(22)
➪P = 132
Then , we will multiply it to the number of hexagoal posters:
4.)
Get the perimeter
➪P = 225 + 225 + 95 + 95
➪P = 640 Cm
5.)
If the diamond has 4 sides, and each is 20 meters. 4 sides × 20 meters = 80 meters
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Answers & Comments
Answer:
1.) 32 meters
2.) 480 meter
3.) 1980
4.) 640 cm
5.) 80 meters
STEP BY STEP SOLUTION:
1.)
Solution:
➪2(length+width)
➪2(10+6)
First, we solve the equation inside the parentheses which is 10 plus 6
10 + 6 = 16
Since "2" is just next to the parenthese we just simply multiply 2 with 16
16 x 2 = 32 meters
2.)
Since a square has 4 equal sides, the length of wire needed is 4 times the length of one side.
➪P = 4(120)
➪P = 480 m
3.)
First , we will solve for the perimeter of the regular hexagon:
➪P = 6(side)
➪P = 6(22)
➪P = 132
Then , we will multiply it to the number of hexagoal posters:
4.)
Get the perimeter
➪P = 225 + 225 + 95 + 95
➪P = 640 Cm
5.)
If the diamond has 4 sides, and each is 20 meters. 4 sides × 20 meters = 80 meters