Answer:
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In 9 years, 8500 amount to 15385 at the rate of 9% per annum.
Step-by-step explanation:
Given that,
Principal, P = 8500
Amount received = 15385
So, Simple interest, SI = Amount - P = 15385 - 8500 = 6885
Rate of interest, r = 9 % per annum
Let assume that the time period be n years.
We kmow, Simple interest (SI) received on a certain sum of money of P invested at the rate of r % per annum for n years is
[tex] \sf \: SI = \dfrac{P \times r \times n}{100} \\ [/tex]
[tex] \sf \: 6885 = \dfrac{8500 \times 9 \times n}{100} \\ [/tex]
[tex] \sf \: 6885 = 85 \times 9 \times n \\ [/tex]
[tex] \sf \: 765 = 85 \times n \\ [/tex]
[tex]\implies\sf\:n = 9 \\ [/tex]
Hence, In 9 years, 8500 amount to 15385 at the rate of 9% per annum
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Answers & Comments
Answer:
ufiddiddiidididdidfjxdkddididdoxifofofo
Verified answer
Answer:
In 9 years, 8500 amount to 15385 at the rate of 9% per annum.
Step-by-step explanation:
Given that,
Principal, P = 8500
Amount received = 15385
So, Simple interest, SI = Amount - P = 15385 - 8500 = 6885
Rate of interest, r = 9 % per annum
Let assume that the time period be n years.
We kmow, Simple interest (SI) received on a certain sum of money of P invested at the rate of r % per annum for n years is
[tex] \sf \: SI = \dfrac{P \times r \times n}{100} \\ [/tex]
[tex] \sf \: 6885 = \dfrac{8500 \times 9 \times n}{100} \\ [/tex]
[tex] \sf \: 6885 = 85 \times 9 \times n \\ [/tex]
[tex] \sf \: 765 = 85 \times n \\ [/tex]
[tex]\implies\sf\:n = 9 \\ [/tex]
Hence, In 9 years, 8500 amount to 15385 at the rate of 9% per annum