[tex]\) As given (5x²+14x+2)²−(4x²−5x+7)² is divided by x²+x+1 <=((5x²+14x−5)−(4x²−5x+7))((5x²+14x+2)+(4x²−5x+7)) =(5x²+14x+2−4x²+5x−7)(5x²+14x+2+4x²−5x+7) <=(x²+19x−5)(9x²+9x+9) =(x²+19x−5)9(x²+x+1) Now dividing by x²+x+1 \ \textless \ br /\ \textgreater \ \ \textless \ br /\ \textgreater \ \frac{x2+x+1}{(x2+19x−5)9(x2+x+1)} (x2+19x−5)9(x2+x+1)x2+x+1\ \textless \ br /\ \textgreater \ \ \textless \ br /\ \textgreater \ Quotient=9(x2+19x−5)andReminder=0\ \textless \ br /\ \textgreater \ \ \textless \ br /\ \textgreater \ [/tex]
If you like my answer, please mark it as ✔️BRAINLIEST! Good Luck and have a nice day!! :)
Answers & Comments
Verified answer
Answer:
As given (5x
2
+14x+2)
2
−(4x
2
−5x+7)
2
is divided by x
2
+x+1
=((5x
2
+14x−5)−(4x
2
−5x+7))((5x
2
+14x+2)+(4x
2
−5x+7))
=(5x
2
+14x+2−4x
2
+5x−7)(5x
2
+14x+2+4x
2
−5x+7)
=(x
2
+19x−5)(9x
2
+9x+9)
=(x
2
+19x−5)9(x
2
+x+1)
Now dividing by x
2
+x+1
=
x
2
+x+1
(x
2
+19x−5)9(x
2
+x+1)
Quotient=9(x
2
+19x−5)andReminder=0
Explanation:
PLS MARK AS BRAINLIEST
Answer:
Quotient=9(x
2
+19x−5)andReminder=0
Explanation:
verified
Verified by Toppr
Correct option is B)
As given (5x
2
+14x+2)
2
−(4x
2
−5x+7)
2
is divided by x
2
+x+1
=((5x
2
+14x−5)−(4x
2
−5x+7))((5x
2
+14x+2)+(4x
2
−5x+7))
=(5x
2
+14x+2−4x
2
+5x−7)(5x
2
+14x+2+4x
2
−5x+7)
=(x
2
+19x−5)(9x
2
+9x+9)
=(x
2
+19x−5)9(x
2
+x+1)
Now dividing by x
2
+x+1
=
x
2
+x+1
(x
2
+19x−5)9(x
2
+x+1)
Quotient=9(x
2
+19x−5)andReminder=0