Using Heron's Formula,
A = √(s(s-a)(s-b)(s-c))
As, s = (a+b+c)/2
s = (4+3+5)/2
s = 6 units
Putting the values,
A = √(6(6-4)(6-3)(6-5))
⇒ A = √(6(2)(3)(1))
⇒ A = √(36) = 6 in2
∴ The area of the triangle is 6 in²
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Answers & Comments
by heron's formula,
Area of the triangle =s(s−a)(s−b)(s−c)
We know, s = 3+4+5
= 6
∴ Area of triangle =6(6−3)(6−4)(6−5)
=6×3×2×1
=6cm2
☆ hope it helps ☆
Verified answer
[tex] ↬\large{\boxed{ \boxed{ \bf{ \pink{Solution}}}}}[/tex]
Given
To find:
Using Heron's Formula,
A = √(s(s-a)(s-b)(s-c))
As, s = (a+b+c)/2
s = (4+3+5)/2
s = 6 units
Putting the values,
A = √(6(6-4)(6-3)(6-5))
⇒ A = √(6(2)(3)(1))
⇒ A = √(36) = 6 in2
∴ The area of the triangle is 6 in²