[tex] \sf\huge \red{QUESTION}[/tex]
[tex] \sf \blue{WHICH \: OF \: THE \: FOLLOWING} \\ \sf \blue{IS \: CORRECT \: FOR \: EQUATION} [/tex]
[tex] \sf\orange{{x}^{2} - 3x + 2}[/tex]
[tex] \sf \pink{(1) \: y-x \: is downward \: parabola}[/tex]
[tex] \sf\pink{(2) \: Maximum \: value \: of \: y \: is \: at \: x = 0}[/tex]
[tex] \sf \pink{(3) \: Intercept \: on \: the \: x-axis \: are} \\ \sf \pink{x = 2 \: and \: x = 3}[/tex]
[tex] \sf \pink{ (4) \: y \: is \: increasing \: from } \\ \sf \pink{x = 1.5 \: to \: x \: → \infty }[/tex]
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Verified answer
Answer:
Explanation:
(4) option is correct
(1) y - x can be a downward parabola if the co-efficient of x² is negative
since the equation has its co - efficient of x² as 1 which is positive
itll be an upward parabola so option (1) incorrect
(2) for this equation it is an upward parabola so we can only tell the minimum value we cannot tell the maximum value
so option (2) incorrect
(3) intercept on the x - axis will be the zeros of the equation
Given the intercepts are x =2 and x = 3
Sub x = 2,3 in the equation
2² -3*2 + 2 = 4 - 6 +2 = 6 -6 = 0
3² - 3*3 + 2 = 9 - 9 +2 = 2
Since x = 3 is not a zero
option (3) is incorrect
(4)
when x = 1.5
(1.5)² - 3*1.5 +2
2.25 - 4.5 +2
-2.25+2 = -0.25
When x = 2
it is 0 as we found earlier'
when x= 3
it is 2 as we found earlier
so y incrasing x = 1.5 to infinity
so option (4) is correct