A bus leaves Manila at 22:10 H on Thursday and arrives in Baguio
[tex]6 \: \frac{1}{2} [/tex]
hours later. At what time and day did the bus arrive in Baguio? Express your answer both in 12 hour format and 24 hour clock formats.
---KAHIT WALANG EXPLANATION NAMAN PO---
[tex]6 \: \frac{1}{2} [/tex]
hours later. At what time and day did the bus arrive in Baguio? Express your answer both in 12 hour format and 24 hour clock formats.
---KAHIT WALANG EXPLANATION NAMAN PO---
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Answer:
The bus arrived in Baguio at 4:40 a.m. or 04:40 H, Friday.
Step-by-step explanation:
Add 6 ½ to 22:10 H, then express the answers both in 12-hour and 24-hour clock formats.
Solve:
22:10 H is the same as 10:10 p.m.
6 ½ hours is the same as 6 hours and 30 minutes.
We will just add 6 hours and 30 minutes to both times.
Explanation:
hours: 22 + 6 = 28 – 24 = 4
There cannot be 28 hours, so we subtract 24 from 28, which means a day has passed, and it is already Friday.
minutes: 10 + 30 = 40
Therefore, the bus arrived in Baguio at 04:40 H, Friday.
Explanation 2:
hours: 10 + 6 = 16 – 12 = 4
There cannot be 16 hours in a 12-hour clock so, we subtract 12 from 16 which means p.m. has passed already; it is already a.m. of the following day, that is Friday.
minutes: 10 + 30 = 40
So, the bus arrived in Baguio at 4:40 a.m., Friday.