Step-by-step explanation:
[tex] log_{a}(ab) = x \\ log_{a}(a) + log_{a}(b) = x \\ 1 + log_{a}(b) = x \\ log_{a}(b) = x - 1 \\ log_{b}(a) = 1 \div (x - 1) \\ log_{b}(a) + log_{b}(b) = 1 \div (x - 1) + log_{b}(b) \\ log_{b}(ab) = 1 \div (x - 1) + 1 \\ log_{b}(ab) = x \div (x - 1) [/tex]
log()()- index
| - base
Copyright © 2024 EHUB.TIPS team's - All rights reserved.
Answers & Comments
Verified answer
Step-by-step explanation:
[tex] log_{a}(ab) = x \\ log_{a}(a) + log_{a}(b) = x \\ 1 + log_{a}(b) = x \\ log_{a}(b) = x - 1 \\ log_{b}(a) = 1 \div (x - 1) \\ log_{b}(a) + log_{b}(b) = 1 \div (x - 1) + log_{b}(b) \\ log_{b}(ab) = 1 \div (x - 1) + 1 \\ log_{b}(ab) = x \div (x - 1) [/tex]
log()()- index
| - base