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hello any one give me 50pts
please complete 540 followers
if a man Travels at a speed of 30 km per hour he reaches his destination 10 minutes late and if he travels at a speed of 40 km per hour in this destination 10 minutes early the distance travel eat
Answers & Comments
Verified answer
Let the distance be x km.
Then, correct time at a speed of
30 km / h = x30 - 1060
Correct time at a speed of 42 km /h
= x42 + 1060
=> x30 - 1060 = x42 + 1060
=> x30 - x42 = 26
=> x(12)1260 = 26
=> 72 x = 1260 × 2
=> x = 1260×272 => x = 35 km
Please mark me Brainliest
Let T is the actual time taken to reach the destination by man.
case 1 : if the speed of man , u = 30 km/h , he reaches his destination 10 min late .
e.g., distance between man and destination point , S = speed of man × time taken
= 30 × (T + 1/6) km [ as you know, 10min = 10/60 hour = 1/6 hour ]
so, S = 30(T + 1/6) - (1)
case 2 : if the speed of man, v = 42 km/h , he reaches his destination 10 minutes early.
e.g.,. distance between man and destination point , S = speed of man × Time taken
= 42 × (T - 1/6) km
so, S = 42(T - 1/6) -(2)
from equations (1) and (2),
30(T + 1/6) = 42(T - 1/6)
or, 10T + 10/6 = 14T - 14/6
or, 10/6 + 14/6 = 14T - 10T
or, 24/6 = 4T
or, T = 1 hour
putting T = 1 in equation (1),
S = 30(1 + 1/6) = 30 × 7/6 = 35 km
hence, The distance travelled is 35 km
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