what is the value of
[tex]t[/tex]
that will make the roots of the equation
[tex] {8}^{2} - 4tx + 3 = 0[/tex]
equal?
a
[tex]t = - + 6[/tex]
b
[tex]t = - + 96[/tex]
c
[tex]t = - + \sqrt{6} [/tex]
d
[tex]t = - + 4 \sqrt{6} [/tex]
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Answers & Comments
Answer:
hah basic
Step-by-step explanation:
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