[tex] \bf \: given \: eq. : - \\ \sf \: x - 3y = - 4 \: \: \: \: \: \: \: \: (1) \\ \sf \: x - 2y = 10 \: \: \: \: \: \: \: \: \: (2) \\ \\ \bf \: now \: subtract \: eq. \: (2) \: from \: eq.(1) \\ \sf \: x - 3y = - 4 \\ \underline{ \sf \: x - 2y = 10} \\ \sf - 3y + 2y - 10 - 4 \\ \sf - y = - 14 \\ \boxed{ \red{\sf \: y = 14}} \\ \\ \sf \: put \: the \: value \: of \: y = 14 \: in \: eq.(1) \\ \sf \: x - 3(14) = - 14 \\ \sf x - 42 = (- 14 )\\ \sf \: x = - 14 + 42 \\ \boxed{\sf \red{ x = 28}} \\ [/tex]
Copyright © 2024 EHUB.TIPS team's - All rights reserved.
Answers & Comments
[tex] \bf \: given \: eq. : - \\ \sf \: x - 3y = - 4 \: \: \: \: \: \: \: \: (1) \\ \sf \: x - 2y = 10 \: \: \: \: \: \: \: \: \: (2) \\ \\ \bf \: now \: subtract \: eq. \: (2) \: from \: eq.(1) \\ \sf \: x - 3y = - 4 \\ \underline{ \sf \: x - 2y = 10} \\ \sf - 3y + 2y - 10 - 4 \\ \sf - y = - 14 \\ \boxed{ \red{\sf \: y = 14}} \\ \\ \sf \: put \: the \: value \: of \: y = 14 \: in \: eq.(1) \\ \sf \: x - 3(14) = - 14 \\ \sf x - 42 = (- 14 )\\ \sf \: x = - 14 + 42 \\ \boxed{\sf \red{ x = 28}} \\ [/tex]