[tex]r \: is \: a \: 1 \: digit \: number \\ thus \: r \: is \: a \: number \: from \: 1 \: to \: 9 \\ if \: we \: divide \: from \: 1 \: to \: 10 \: numbers \: \\ we \: get \: that \: 3 \: is \: only \: divisible \: in \: r \: place \\86, 372/11 we \: get \: 7852.. \\ if \: we \: divide \: any \: number \: from \: 1 \: to \: 10 \: \\ except \: 3 \: we \: get \: all \: answers \: in \: ..points.. \\ thus \: r = 3..[/tex]
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[tex]r \: is \: a \: 1 \: digit \: number \\ thus \: r \: is \: a \: number \: from \: 1 \: to \: 9 \\ if \: we \: divide \: from \: 1 \: to \: 10 \: numbers \: \\ we \: get \: that \: 3 \: is \: only \: divisible \: in \: r \: place \\86, 372/11 we \: get \: 7852.. \\ if \: we \: divide \: any \: number \: from \: 1 \: to \: 10 \: \\ except \: 3 \: we \: get \: all \: answers \: in \: ..points.. \\ thus \: r = 3..[/tex]
(8+R+2)-(6+7)=Either 0 or 11
=(10+R)-11=Either 0 or 11
We know that 11-11=0
Hence the shortest possible value of R is 1
Just ask a new question I will reply there