if the value of atmospheric pressure
[tex]10 ^{6} dynes \: \: per \: cm^{2} then \: find \: its \: value \: in \: si \: system[/tex]
[tex]10 ^{6} dynes \: \: per \: cm^{2} then \: find \: its \: value \: in \: si \: system[/tex]
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As We Know,
1N = 10^5 dyne
→10^-5N = 1 dyne
→10N = 10^6 dyne
And,,
1cm = 10^-2m
1cm^2 = 10^-4m^2
So,
10^6 dyne/cm^2
= 10 N/10^-4m^2
= 10^5 N/m^2
Si unit of pressure = N/m^2 = pa
As We Know, SI Unit Of Pressure = Pa
So We Can Say, 10^5 pa.
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#hope helped (:
1N = 10^5 dyne
10^-5N = 1 dyne
10N = 10^6 dyne
Also
1cm = 10^-2m
1cm^2 = 10^-4m^2
Therefore
10^6 dyne/cm^2
= 10 N/10^-4m^2
= 10^5 N/m^2
Si unit of pressure = N/m^2 = pa
As We Know, SI Unit Of Pressure = Pa
So its value is 10^5 pa
#skb❤