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(secø-coso) (cotø + tanø) =tanø x secø
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(secø-coso) (cotø + tanø) =tanø x secø
[tex]\huge{\mid{\underline{\overline{\tt Disclaimer!}} \mid}}[/tex]
•dont spam
• worng answer strictly prohibited
Answers & Comments
Verified answer
Step-by-step explanation:
Step 1: Use the distributive property to expand the expression: (cotø + tanø) = cotø x 1 + tanø x 1 Step 2: Use the Pythagorean identity to rewrite the expression: cotø x 1 + tanø x 1 = cotø x secø x secø + tanø x secø x secø Step 3: Simplify the expression: cotø x secø x secø + tanø x secø x secø = secø x secø (cotø + tanø) Step 4: Simplify the expression: secø x secø (cotø + tanø) = tanø x secø x secø