Answer:
Given Equation:
[tex]x^{2} +(y-3\sqrt{2x})^{2} =1[/tex]
Step-by-step explanation:
[tex]x^{2} +y^{2} -6\sqrt{2x}+18x=1\\ Taking\ square\ on\ both\ sides:\\x^{4}+y^{4} -72x+324x^{2} =1[/tex]
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x²+(y-3√2x)2
x² + y²-6√2x + 18x 1 Taking square on both sides: x² + y¹ - 72x + 324x² = 1
Mannat
9th
from haryana
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Answers & Comments
Answer:
Given Equation:
[tex]x^{2} +(y-3\sqrt{2x})^{2} =1[/tex]
Step-by-step explanation:
[tex]x^{2} +y^{2} -6\sqrt{2x}+18x=1\\ Taking\ square\ on\ both\ sides:\\x^{4}+y^{4} -72x+324x^{2} =1[/tex]
Kindly share me the full question then I will be solve;
[email protected]
that's my email you can also contact with me on brainly.in by click on my id.
Answer:
Given Equation:
x²+(y-3√2x)2
Step-by-step explanation:
x² + y²-6√2x + 18x 1 Taking square on both sides: x² + y¹ - 72x + 324x² = 1
Mannat
9th
from haryana