Hello User!!
Description:-
As you asked how to type the format, I'm here to help you. So this format is called latex. Now, the easiest way to use it is in the attachments.
In the first attachment,
you will see the object where you have to click it.
you'll see the condition after clicking the box.
Now use it and keep helping others (•‿•)
Hello Mathemagicians!!
Here's one more!!
[tex] \displaystyle \int^4_2 \: \frac{ \sqrt{x} }{ \sqrt{6 - x} + \sqrt{x} } dx[/tex]
Don't spam!
Description:-
As you asked how to type the format, I'm here to help you. So this format is called latex. Now, the easiest way to use it is in the attachments.
In the first attachment,
you will see the object where you have to click it.
you'll see the condition after clicking the box.
Now use it and keep helping others (•‿•)
Hello Mathemagicians!!
Here's one more!!
[tex] \displaystyle \int^4_2 \: \frac{ \sqrt{x} }{ \sqrt{6 - x} + \sqrt{x} } dx[/tex]
Don't spam!
Answers & Comments
Verified answer
Answer:
[tex]\boxed{\displaystyle \int_2^4 \dfrac{\sqrt x}{\sqrt{6-x}+\sqrt x} = 1}[/tex]
Step-by-step explanation:
[tex]Let \ I = \displaystyle \int_2^4 \dfrac{\sqrt x}{\sqrt{6-x}+\sqrt x}~~~~\cdotp\cdotp\cdotp(1)\\\\\text{Using property, }\boxed{\int_a^bf(x) dx = \int_a^bf(a+b-x)dx}\\\\I = \int_2^4\dfrac{\sqrt{6-x}}{\sqrt{6-(6-x)}+\sqrt{6-x}}\\\\I = \int_2^4\dfrac{\sqrt{6-x}}{\sqrt{x}+\sqrt{6-x}}~~~~\cdotp\cdotp\cdotp(2)\\\\\text{Adding Equation (1) and (2):}\\\\2I = \int^4_2\left(\dfrac{\sqrt{x}+\sqrt{6-x}}{\sqrt{x}+\sqrt{6-x}\right)dx}\\\\2I = \int_2^4dx\\\\2I = \left[x\right]_2^4\\\\2I = 4 - 2\\\\\boxed{I = 1}[/tex]
Answer:
hi brother I solved a question like this
don't mind now the picture quality is good..