In a book of 600 pages there are 300 misprints. A page of the book is selected at random. The probability that the page have no misprint is
(a) [tex]\dfrac{1}{2e}[/tex]
(b) [tex]\dfrac{1}{2\sqrt{e}}[/tex]
(c) [tex]\dfrac{2}{\sqrt{e}}[/tex]
(d) none of these
(a) [tex]\dfrac{1}{2e}[/tex]
(b) [tex]\dfrac{1}{2\sqrt{e}}[/tex]
(c) [tex]\dfrac{2}{\sqrt{e}}[/tex]
(d) none of these
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Answer:
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Step-by-step explanation:
Here λ=
500
300
=0.6
Hence P(X≥1)=1−P(X=0)=1−
0!
e
−0.6
(0.6)
0
=1−e
−0.6
Then the probability of getting misprint pages =
= P (300)/P (600)
= 1/2
Hence the probability of getting misprint pages is 1/2