If,
[tex]0 \leqslant a < 90[/tex]
Then, the lowest value of
[tex] \sec {}^{2} a + \cos {}^{2} a = [/tex]
(a) 1
(b) 2
(c)
[tex] \frac{5}{2} [/tex]
(d) 0
[tex]0 \leqslant a < 90[/tex]
Then, the lowest value of
[tex] \sec {}^{2} a + \cos {}^{2} a = [/tex]
(a) 1
(b) 2
(c)
[tex] \frac{5}{2} [/tex]
(d) 0
Add an Answer
More Questions From This User See All
Answers & Comments
Answer:
I dont know this answer. how to do this question
Step-by-step explanation:
The lowest value of sec²a + cos²a is (a) 1.