[tex] \huge \fbox\color{red}{question}[/tex]
[tex] {Find the simple interest on rupee 7600 from 16 may 2013 to 9 october 2015 at 10% per annum}[/tex]
[tex] \bold {correct \: answer \: is \: 304 }[/tex]
[tex]please \: give \: me \: explanation[/tex]
Correct Answer will be given 5 stars, a thanks and a brain list
Answers & Comments
Verified answer
Principal, P = 7600
Rate, R = 10%
Duration from 16 may 2013 to 9 october 2015 is 2yr 4 months and 24 days.
2yr 4months 24 days = 2 yr 4.8 month = 2.4 yrs
So time, T = 2.4 yrs
SI = PTR/100
= 7600 × 2.4 × 10 / 100
= ₹ 1824
Hence, Simple interest is 1824.
Given :-
Solution :-
As we know that,
[tex] \begin{gathered}\\ {\underline{\boxed{\large \orange\leadsto\bf { SI = \frac{P \times R \times T}{100} }}}} \\ \end{gathered}[/tex]
Where,
So,
[tex] \begin{gathered}\\ \large\implies\sf{ \frac{7600 \times 2.4 \times 10}{100} } \\ \end{gathered}[/tex]
[tex] \begin{gathered}\\ \large\implies\sf{ \frac{1824}{1} } \\ \end{gathered}[/tex]
Hence,
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