[tex]\huge\underline\bold{Question:}[/tex]
Calculate the mass of :
a) 0.5 mole of silver Ag-108
b) 0.5 mole of sugar (C12H22O11)
Calculate the mass of :
a) 0.5 mole of silver Ag-108
b) 0.5 mole of sugar (C12H22O11)
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Answer:
= 12 × 12 + 22 × 1 u + 11 × 16 u = 342 u or 342 g/mol Now, to calculate mass, apply the formula: We can write: Mass(m) = Number of moles (n) × Molar mass of C12H22O11 (M) Mass = 0.5 mol × 342g/mol Mass = 171g Thus, the mass of 0.5 mole of sugar (C12H22O11) is 171g.
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Answer:
a) the mass of 0.5 mole of silver is equal to 54g.
b) thus, the mass of 0.5 mole of sugar (C12 H22 O11) is 171g.