[tex]\ \textless \ br /\ \textgreater \ \ \textless \ br /\ \textgreater \ \huge\green{\boxed {\bf{\pmb{\gray{Question:-}}}}}[/tex]
By travelling at 40 kmph, a person reaches his destination on time. He covered two-third the total distance in one-third of the total time. What speed should he maintain for the remaining distance to reach his destination on time?
A. 15 kmph
B. 20 kmph
C. 25 kmph
D. 30 kmph
Answers & Comments
Answer:
B is right answer.
i hope it will help you
Step-by-step explanation:
Let the time taken to reach the destination be 3x hours.
Total distance = 40 * 3x = 120x km
He covered 2/3 * 120x = 80x km in 1/3 * 3x = x hours
So, the remaining 40x km, he has to cover in 2x hours. Required speed = 40x/2x = 20 kmph
Verified answer
Given:
To find:
Concept:
[tex]\;\red{\boxed{\gray{\;\textsf{\textbf{Speed}}=\dfrac{\textsf{\textbf{Distance}}}{\textsf{\textbf{Time taken}}}\;}}}
[/tex]
Calculations:
So, total distance = 40 × 3t = 120t km.
As it is given that, he covered two-third the total distance in one-third of the total time.
Therefore,
[tex] = \frac{2}{3} \times 120t[/tex]
[tex] = 2 \times 40t[/tex]
[tex] = 80[/tex]
And ,
[tex] = \frac{1}{3} \times 3t[/tex]
[tex] = 1 \times t[/tex]
,
[tex] = t[/tex]
So, the remaining distance 120t - 80t = 40t km, he has to cover in 3t - t = 2t hours time.
• Distance = 40t km
• Time taken = 2t hours time
[tex]speed = \frac{distance}{time \: taken} [/tex]
[tex]speed = \frac{40t}{2t} [/tex]
[tex]speed = \frac{40}{2} [/tex]
speed =20kmph
so, option (B) is the correct