[tex]\huge\mathcal{\fcolorbox{pink} {beige} {\blue{Question}}}[/tex]
At
25
∘
C
and
760
m
m
of
H
g
pressure a gas occupies
600
m
L
volume. What will be its pressure at a height where temperature is
10
∘
C
and volume of the gas is
640
m
L
.
At
25
∘
C
and
760
m
m
of
H
g
pressure a gas occupies
600
m
L
volume. What will be its pressure at a height where temperature is
10
∘
C
and volume of the gas is
640
m
L
.
Answers & Comments
Answer:
shopkeeper sells his article by giving 8% discount and again he charges 6% sells if customer is getting 1 article at Rs 243.50 what is the market price of an article
Verified answer
[tex]\huge\green {\underline {\mathfrak {Answer:}}}[/tex]
[tex]\frac{P_1 \cdot V_1}{T_1} = \frac{P_2 \cdot V_2}{T_2} [/tex]
where:
- P1 is the initial pressure,
- \(V_1\) is the initial volume,
- \(T_1\) is the initial temperature (in Kelvin),
- \(P_2\) is the final pressure,
- \(V_2\) is the final volume,
- \(T_2\) is the final temperature (in Kelvin).
Given:
\(P_1 = 760 \, \text{mmHg}\),
\(V_1 = 600 \, \text{L}\),
\(T_1 = 25^\circ \text{C}\) (convert to Kelvin: \(T_1 = 25 + 273.15\)),
\(V_2 = 640 \, \text{L}\),
\(T_2 = 10^\circ \text{C}\) (convert to Kelvin: \(T_2 = 10 + 273.15\)).
Now plug in these values into the formula and solve for \(P_2\).