Evaluate [tex]\displaystyle \rm\int\limits_{1}^{2} 3^{x} \ \ d x[/tex] as a limit of a sum.
[tex] \color{darkcyan}\boxed{ \underline{\underline{ \text{Answer :-}}}} \\ \\ \bigstar \boxed{ \implies \rm\log_{3}(e) }[/tex]
[tex] \rule{300pt}{0.1pt}[/tex]
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Answer:
Here,
Lower limit, a = 0
Upper limit, b = 2
Step:- 1
where h is the width of interval and n is number of intervals of width h
Step :- 2
Put x = a + rh = 0 + rh = rh
So, above expression can be rewritten as
Step :- 3
By definition of Limit as a Sum,
So, on substituting the values, we get
Now, first term forms a GP series, so using sum of n terms, we get
Hence,
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Formulae Used
1. Sum of n terms of GP series having first term a and common ratio r respectively is given by
2. Sum of first n natural numbers is given by
3. Limit result
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ADDITIONAL INFORMATION
Step-by-step explanation: