[tex]\bold{\huge{\boxed{Hey guys}}}[/tex]....answer this..... Created by samruddhi9875. Math

tex]....answer this...

AJAYMAHICH Mode = [l1 + {(f1-fo) / (2f1-fo-f2) }*h]

65 = 60 + {( 12-f1) / (2(12) - f1 - 6 ) } * 20

5/ 20 = (12-f1)/ ( 18-f1)

1/4 = (12-f1) / (18-f1)

18-f1 = 48 - 4f1

3f1 = 30

f1 = 10

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