[tex]the \: length \: and \: breadth \: of \: a \: rectangle \: are \: 60cm \: and \: 30cm \: repectively.find \: the \: ratio \: of \: its \\ \\ \\ \\ a.length \: to \: breadth \\ \\ length \: to \: perimeter \: \\ \\ c.area \: to \: perimeter[/tex]
Add an Answer
More Questions From This User See All
Answers & Comments
Step-by-step explanation:
Given that,
Number of turns N=60
Length l=20cm
Width b=10cm
Magnetic field B=0.5T
Rotation per min f=1800
We know that,
ϕ=(ABcosθ)N
ϕ=NABcosωt
dt
−dϕ
=ε
ε=−
dt
d(NABcosωt)
ε=−ABω(−sinωt)N
ε=NABωsinωt
ω=2πf
ε=2πfNABsinωt
ε
max
=2πfNAB
ε
max
=2×3.14×60×(20×10×10
−4
)×0.5×30
ε
max
=113.04volt
Hence, the maximum induced emf is 113.04volt
Answer:
number to bhej bhen ya formula mang rahi hai