IF THE QUADRATIC EQUATION IS NOT IN STANDARD FORM,TRANSFORM INTO AX²+BX+C=0A ND DETERMINE THE VALUE OF A,B AND C.
[tex]1.7x - 12 = x {}^{2} \\ 2.7x - 4 + 4x {}^{2} = 0 \\ 3.25 - 10x = - x { }^{2} \\ 4.5x + 4 = 2x {}^{2} \\ 5.x {}^{2} = 4x + 20[/tex]
[tex]1.7x - 12 = x {}^{2} \\ 2.7x - 4 + 4x {}^{2} = 0 \\ 3.25 - 10x = - x { }^{2} \\ 4.5x + 4 = 2x {}^{2} \\ 5.x {}^{2} = 4x + 20[/tex]
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Answer:
1. - x²+7x-12=0
A= - 1, B=7 and C= - 12
2. 4x²+7x-4=0
A=4, B=7 and C= - 4
3. -x²-10x+25=0
A= -1, B= -10 and C=25
4. -2x²+5x+4=0
A= -2, B=5 and C=4
5.x²-4x-20=0
A=1, b= -4 and C= -20