.

.

.

Given :-

Acceleration of trolley, a = 2 cm/s² = 0.02 m/s²

Initial speed of trolley, u = 0 (As trolley starts from rest)

Time taken by trolley, t = 3 seconds

To Find :-

Final speed, v = ??

Formula to be used :-

1st equation of motion,

i.e, v = u + at

Solution :-

Putting all the values, we get

v = u + at

⇒ v = 0 + 0.02 × 3

⇒ v = 0.02 × 3

⇒ v = 0.06 m/s

Hence, the final velocity of trolley is 0.06 m/s.

Important Term :-

Final speed - Final speed is that speed which is acquired by the body after its start. It is denoted by v. When a body finally comes to rest, its final speed is zero.

Initial velocity (u) = 0 ( as the trolley begins from the rest position)

Acceleration (a) = 0.02 ms-2

Time (t) = 5s

Find out

velocity 5s after the start

Formula

As per the first motion equation,

v = u + at

(v) = 0 + (0.02 ms-2)(5s)

Putting all the values

we get

⇒v = u + at

⇒v = 0 + 0.02 × 5

⇒v = 0.02 × 5

⇒ v = 0.10 m/s

⇒ 0.10 m/s

Therefore, the velocity of the trolley after 5 seconds will be 10 m/s

hope it was helpful to you