Answer:
Fencing is done at the perimeter so, perimeter of rectangular park=2(l+b)
[tex] = 2 \times 50 + 45m \\ \\ = 2 \times 95m \\ \\ = 190m[/tex]
Rate of fencing per meter=Rs 4
Rate of fencing 190m=190×4
=Rs 760
[tex] \rule{190pt}{2.5pt}[/tex]
Given :
To Find :
Solution :
As, We know that :
★ Perimeter of Rectangle = 2(L+B)
Here,
=⟩ 2(L+B)
=> 2( 50+45 )
=> 2( 95 )
=> 190m
Therefore, 190m will be fenced.
★ Cost of 1m fence = Rs. 4
Cost of 190m fence = 190 × 4
=> Rs. 760
Therefore, Rs. 760 will be needed to fence the rectangular field.
★ Perimeter formulas ★
Triangle = Sum of All sides
Square = 4 × Sides
Circle = 2πr = πd
Rectangle = 2(L+B)
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Answers & Comments
Answer:
Fencing is done at the perimeter so, perimeter of rectangular park=2(l+b)
[tex] = 2 \times 50 + 45m \\ \\ = 2 \times 95m \\ \\ = 190m[/tex]
Rate of fencing per meter=Rs 4
Rate of fencing 190m=190×4
=Rs 760
[tex] \rule{190pt}{2.5pt}[/tex]
Additional information:-
Verified answer
Answer:
Given :
To Find :
____________________
Solution :
As, We know that :
★ Perimeter of Rectangle = 2(L+B)
Here,
=⟩ 2(L+B)
=> 2( 50+45 )
=> 2( 95 )
=> 190m
Therefore, 190m will be fenced.
____________________
★ Cost of 1m fence = Rs. 4
Cost of 190m fence = 190 × 4
=> Rs. 760
Therefore, Rs. 760 will be needed to fence the rectangular field.
____________________
More Information:
★ Perimeter formulas ★
Triangle = Sum of All sides
Square = 4 × Sides
Circle = 2πr = πd
Rectangle = 2(L+B)