[tex]\huge\blue{\mid{\underline{\overline{\tt Question:}} \mid}}[/tex]
(A) In a Quadrilateral ABCD, bisectors of ∠A and ∠B intersect at O such that ∠AOB = 75°, then write the value of ∠C + ∠D.
(B) In a Parallelogram ABCD, if ∠A = (3x - 20)°, ∠B = (y + 15)°, ∠C = (x + 40)°, then find the values of x and y.
(C) Prove that the line segment joining the mid-point of the diagonals of a trapezium is parallel to each of the parallel sides and is equal to half the difference of these sides.
OR
Show that the Quadrilateral formed by joining the mid-points of the consecutive sides of a square is also a square.
Answers & Comments
Answer:
the answer can be found by equating
Step-by-step explanation:
3x-20+ y+15+x+40=180
Answer:
hi
Step-by-step explanation:
can I know which class this is so i can answrr