[tex]\huge\mathfrak\pink{question}[/tex]
A free pith ball P of 10 g carries a positive charge of 5 x 10-8 C. What must be the nature and magnitude of charge that should be given to another pith ball Q fixed 7 cm below the former ball, so that upper ball is stationary?
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Answer:
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Step-by-step explanation:
q1=5×10−8C,r=7cm=7×10−2m q 1 = 5 × 10 - 8 C , r = 7 c m = 7 × 10 - 2 m Second ball Q must carry positive charge so that force of repulision balances the weight of ball P. When ball remains stationary
Answer:-
q1=5×10−8C,r=7cm=7×10−2m q 1 = 5 × 10 - 8 C , r = 7 c m = 7 × 10 - 2 m Second ball Q must carry positive charge so that force of repulision balances the weight of ball P. When ball remains stationary.
Step-by-step explanation:
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