Explanation:

To find the initial velocity (\(v_0\)), differentiate the given function with respect to time (\(t\)) to get the velocity function (\(v(t)\)). Then, evaluate \(v(t)\) at \(t = 0\).

For initial acceleration (\(a_0\)), differentiate \(v(t)\) with respect to \(t\) to get the acceleration function (\(a(t)\)), and evaluate at \(t = 0\).

For acceleration at \(t = 1\) sec, simply substitute \(t = 1\) into the acceleration function.

Let's calculate these:

(a). Initial velocity:

\[v(t) = 3x^2 - 6x \quad \text{(differentiate)}\]

Evaluate at \(t = 0\):

\[v_0 = 3(0)^2 - 6(0) = 0\]

(b). Initial acceleration:

\[a(t) = 6x - 6 \quad \text{(differentiate)}\]

Evaluate at \(t = 0\):

\[a_0 = 6(0) - 6 = -6\]

(c). Acceleration at \(t = 1\) sec:

\[a(1) = 6(1) - 6 = 0\]

Answer:

Explanation:

Write the outputs of the SQL queries(i)to(iii) based on the relations Car and Customer given below:

Car

Ccode Cname Make Colour Capacity Charges

201 Triber Renault Yellow 7 1000

203 Altroz Tata Black 5 1500[tex]GHGHGH[/tex]

208 Innova Toyota Silver 8 3000

209 Harrier Tata White 6 2000

212 Duster Renault Red 6 2500

217 Ertiga Suzuki Grey 7 2300

Customer

Custcode Custname Ccode

101 Gopinath 201

102 Ashok 203

103 Harshini 209

104 Vishnu 212

i. Select make, count(*) from Car group by make having  count(*)<2;

ii. Select Cname, Make from Car order by charges desc;