Verified answer

Answer:

1013.33 mm of Hg

Explanation:

V1=850ml

V2= 850 × 75/100

= 850×3 / 4

P1 = 760 mm of Hg

P2 = ?

At costant temperature P1V1 = P2V2

therefore , P2 = P1V1/V2

P2 = 760 × 850

850 × 3

4

= 760 × 850 × 4

850 × 3

= 1013.33 mm of Hg

HOPE IT HELPS

[tex]{\tt{Answer}}[/tex]

✿ Given: [tex]\sf{V_1=850\:ml}[/tex]

✿ We know that [tex]\sf{75\%=\frac{75}{100} }[/tex] [tex]\sf{(Because\:percentage\:means\:out\:of\:hundred)}[/tex]

[tex]\sf{V_2=850\times\frac{75}{100}=\frac{850\times3}{4} }[/tex] [tex]\sf{(\frac{3}{4}\:is\:the\:simplest\:form\:of\:\frac{75}{100} )}[/tex]  

✿ Given: [tex]\sf{P_1=750\:mm\:of\:Hg}[/tex]

✿ To find: [tex]\sf{The\:value\:of\:P_2}[/tex]

✿ We know that: [tex]\sf{At\:constant\:temperature, P_1V_1=P_2V_2}[/tex]

Therefore, [tex]\sf{P_2=\frac{P_1V_1}{V_2} }[/tex]

[tex]\sf{=\frac{760\times850\times4}{850\times3} }[/tex]

[tex]\sf{P_2=\frac{760\times4}{3} }[/tex] [tex]\sf{(Cancel\:850\:from\:both\:numerator\:and\:denominator)}[/tex]

[tex]\sf{P_2=\frac{3040}{3}=1013.33\:mm\:of\:Hg\:(In\:decimal\:form)}[/tex]

✿ The final pressure of the gas is 1013.33 mm of Hg.

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Hope it helps :D