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A boy stands 60 m in front of a tall wall and claps. The boy continues to clap every time an echo is heard. Another boy finds that the time taken between the first and fifty-first clap is 18 s. Calculate the speed of sound.
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Answer:
The boy claps only when he hears an echo. Hence the time taken here is the time between successive claps and during this time interval, the wave travels a distance of 120m. Since the time taken between the first and the 51st clap is 18s, time interval between any two claps is 18/(51-1) =0.36secs
The velocity of the sound wave is V=120/0.36 = 333.33 m/s
Explanation:
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The boy claps only when he hears an echo. Hence the time taken here is the time between successive claps and during this time interval, the wave travels a distance of 120m. Since the time taken between the first and the 51st clap is 18s, time interval between any two claps is 18/(51-1) =0.36secs
The velocity of the sound wave is V=120/0.36 = 333.33 m/s