Answer:
3a – 1 ,3a+1, 2a–3
Step-by-step explanation:
Sana makatulong
6a³-23a²+25a-6÷a-2
6a³-23a²+25a-6÷a-2P(x)=6a³-23a²+25a-6÷a-2
6a³-23a²+25a-6÷a-2P(x)=6a³-23a²+25a-6÷a-2P(x)=6a³-23a²+25a-6;a=2
6a³-23a²+25a-6÷a-2P(x)=6a³-23a²+25a-6÷a-2P(x)=6a³-23a²+25a-6;a=2P(2)=6(2)³-23(2)²+25(2)-6
6a³-23a²+25a-6÷a-2P(x)=6a³-23a²+25a-6÷a-2P(x)=6a³-23a²+25a-6;a=2P(2)=6(2)³-23(2)²+25(2)-6 = 48-92+50-6
6a³-23a²+25a-6÷a-2P(x)=6a³-23a²+25a-6÷a-2P(x)=6a³-23a²+25a-6;a=2P(2)=6(2)³-23(2)²+25(2)-6 = 48-92+50-6P(2)=0
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Answers & Comments
Answer:
3a – 1 ,3a+1, 2a–3
Step-by-step explanation:
Sana makatulong
Answer:
a-2
a-2Step-by-step explanation:
6a³-23a²+25a-6÷a-2
6a³-23a²+25a-6÷a-2P(x)=6a³-23a²+25a-6÷a-2
6a³-23a²+25a-6÷a-2P(x)=6a³-23a²+25a-6÷a-2P(x)=6a³-23a²+25a-6;a=2
6a³-23a²+25a-6÷a-2P(x)=6a³-23a²+25a-6÷a-2P(x)=6a³-23a²+25a-6;a=2P(2)=6(2)³-23(2)²+25(2)-6
6a³-23a²+25a-6÷a-2P(x)=6a³-23a²+25a-6÷a-2P(x)=6a³-23a²+25a-6;a=2P(2)=6(2)³-23(2)²+25(2)-6 = 48-92+50-6
6a³-23a²+25a-6÷a-2P(x)=6a³-23a²+25a-6÷a-2P(x)=6a³-23a²+25a-6;a=2P(2)=6(2)³-23(2)²+25(2)-6 = 48-92+50-6P(2)=0
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