Find the zeroes :-[tex]2 {x}^{2} - 2 \sqrt{2} x - 3[/tex]. Created by TANU81. Math

tex]...

gaurav2013c $2 {x}^{2} - 2 \sqrt{2} x - 3 \\ \\ = 2 {x}^{2} - 3 \sqrt{2} x + \sqrt{2} x - 3 \\ \\ = \sqrt{2} x( \sqrt{2} x - 3) + 1( \sqrt{2} x - 3) \\ \\ = ( \sqrt{2} x - 3)( \sqrt{2} x + 1)$

Zeroes are :-

3 / root2 and - 1 / root2

TANU81 Thankyou :)

shivshankar66 Zeroes are :-

3 / root2 and - 1 / root2

TANU81 Hey user , your previous methods are correct why are you edit your answer kindly edit your answer and show full steps irs correct :)

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